Advertisement
WAEC

Waec 2022 Chemistry Questions And Answers

The Waec 2022 Chemistry Questions And Answers are uploaded by the Scholars Learn Team here. It is one of our biggest project to help students who are currently writing the Waec Examination this year so as to scale through difficult subjects and cone out in flying colours.

The West African Examinations Commission (WAEC) is the governing body of the West African Secondary School Leaving Examination (NEC). In one year more than three million people registered for the WAEC exam.

We respect your opinion, and look forward to it. So, if you need to feed us with more up-to-date information about WAEC Chemistry 2022, please give us your phone number and email address in the comment box below.

What is your opinion on this? We believe this article helped. If yes, do not hesitate to share this information with your friends on Facebook, Twitter, and WhatsApp.

In this article, we explore how you can get 2022 WAEC Chemistry questions and answers so that you can be well-prepared for your upcoming WAEC exam, and also understand how WAEC set Chemistry questions and how to answer them. With this guide, you can make good grades on Chemistry WAEC 2022 exam..

Advertisement

Waec 2022 Christian Religious Studies Questions And Answers

(1ai) Lewis acid can be defined as a chemical entity that can accept a pair of electrons from a Lewis base to form a coordinate covalent bond with it.

(1aii)

  1.  copper (Cu2)
  2.  iron (Fe2+ and Fe3+)
  3. hydrogen ion (H+).

(1b) Soap is precipitated as a solid from the suspension by adding common saltto the suspension.

(1d) The percentage abundance of an isotope is the percentage of atoms with a specific atomic mass found in a naturally occurring sample of an element.

(2ai)

Ionization energy can be defined as the energy required to remove a loosely bound electron from the outermost shell of a gaseous covalently bonded atom.

(2aii)

This is because B has more shells than Be which makes the valence electrons to be far from the nucleus making it require less energy due to lesser nuclear attraction.

(2b)

I = 0.12A, t = 500seconds

m = 0.015g, F =96500C

M = 48.0, Charge = ?

Using;

m = MIt/CF

C = MIt/mF

C = (48×0.12×500)/(0.015×96500)

C = 2

(2ci)

Al₂O₃

(2cii)

(i) Electricity supply

(ii) Nearness to source of material

(2di)

This can be defined as a property of metal which are weakly attracted to an applied magnetic field

(2dii)

(i) I → ₂₄Cr²⁺ → 2

₂₄Cr⁶⁺ → 0

(ii) ₂₄Cr²⁺

(iii) It has unpaired electrons.

(3ai) Avogadro’s number, number of units in one mole of any substance (defined as its molecular weight in grams), equal to 6.02214076 × 1023.

(3aii)

Mass/m.m = no. of molecules/Avogadro’s number

(2.30/m.m) × (3.01×10²²/6.02×10²³)

m.m = (2.30×6.02×10²³)/3.01×10²²

m.m = 46g/mol

(3aiii)

Since the molar mass = 46g/mol

The formula is NO₂

:. 14+(16×2)

14+32 = 46g/mol

:. NO₂

(3bi)

(i) There is no reaction but rather forms a layer underneath the water

(ii) It reacts violently with water forming white silicon dioxide and hydrogen chloride gas.

(3bii)

The reaction is different because CCl₄ is an organic substance while SiCl₄ is not.

(3ci)

Extraction of copper

(3cii)

(i) CuSO₄

(ii) CuCl₂

(3ciii)

Cu²⁺ + 2e⁻ —> Cu

(3civ)

Using; m = ZIt

Z = m/It

Z = 3.2/(50x(3×60)+13)

Z = 3.2/(50×193)

Z = 3.2/9650

Z = 0.000332g/Asec

(3d)

Oxygen can be prepared by heating KClO₃ in the presence of manganese(iv)oxide which acts as a catalyst to produce KCl and oxygen gas. The reaction takes place at a lower temperature and much faster rate.

KClO₃ (MnO₂)heat—–> KCl + O₂

(5a)

(i) It melts to clear mobile liquid

(ii) A brownish gas is evolved.

(5bi)

(i) Carbon(ii)oxide

(ii) Lead(ii)oxide

(5bii)

Methane(CH₄)

(5biii)

(i) It leads to erosion

(ii) It causes pollution

(5biv)

This is because it has more surface area than it occupies leading to a faster rate of reaction.

(5bv)

Ammoniacal liquor

(5ci)

When water is added to white anhydrous CuSO₄ it turns blue.

(5cii)

(i) It removes the hardness by precipitating the trioxocarbonate(iv)

(ii) It removes the hardness by removing the calcium or magnesium ion and precipitating trioxocarbonate(iv).

(5ciii)

Ca(HCO₃)₂ → CaCO₃ + H₂O + CO₂

Related Articles

Leave a Reply

Your email address will not be published. Required fields are marked *

Advertisement
Back to top button